Automotive Electric car «J1772» charger «pilot» signal sequencing …

5 мая 2014 | Author: | Комментарии к записи Automotive Electric car «J1772» charger «pilot» signal sequencing … отключены
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Electric car “J1772” charger “pilot” signal sequencing passive circuitry


background: Many electric are designed to use a J1772 charging The main signal in the J1772 is called the pilot.

Long short, the car is expected to place a and diode in series across the and ground. A resistor value of indicates that the car is present, and a of 882 ohms indicates that the car to have power.

The spec requires that you a stopover in state B (2.74k) engaging state C (882). It not say how long that stopover be.

There is a second signal in the called Proximity. It is a signal the J1772 handle to the car. It is to the release button on the handle.

the user is pushing on that it is a 450 ohm resistance to ground and when the is released, it is a 150 ohm resistance.

My Device

I am making a device has a J1772 inlet and derives its from the charger to which it is Prior to it placing the 882 ohm resistor in place, it has no power of its own (unlike electric cars).

The natural to do would be to make a circuit that when that is 150 ohms, the extra 1.3 kOhm between the pilot and ground is in When the resistance is, oh, greater 300 ohms, that resistor is not in

The challenge is. how can one do that with passive components?

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In short, I to detect whether a particular pin has a of less than 300 ohms to and if it does, I want to change the between another pin and ground 2.74k to 882 ohms (or put another add another 1.3 kohms in parallel). And I strongly prefer to do this a power source.

The left half of the diagram is the proximity circuit that’s of the J1772 charging handle. It be changed. The right hand is my circuit.

The question, again, is the proximity resistance is less 300 ohms, I want to close the switch.

If I were going to make active, this is what it be:

This may be laughable overkill. not sure. But it doesn’t solve the problem. It requires either a set of AA (3 would last around 100 if my calculations are correct), or a START across the transistor to bootstrap the

Both of those solutions, in my are lame.

Rinspeed XchangE Electric Cars
Rinspeed XchangE Electric Cars
Rinspeed XchangE Electric Cars
Rinspeed XchangE Electric Cars
Rinspeed XchangE Electric Cars
Rinspeed XchangE Electric Cars
Rinspeed XchangE Electric Cars

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